Optimal. Leaf size=214 \[ \frac{(d+e x)^{5/2} (-7 a B e+5 A b e+2 b B d)}{5 b^2 (b d-a e)}+\frac{(d+e x)^{3/2} (-7 a B e+5 A b e+2 b B d)}{3 b^3}+\frac{\sqrt{d+e x} (b d-a e) (-7 a B e+5 A b e+2 b B d)}{b^4}-\frac{(b d-a e)^{3/2} (-7 a B e+5 A b e+2 b B d) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{b^{9/2}}-\frac{(d+e x)^{7/2} (A b-a B)}{b (a+b x) (b d-a e)} \]
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Rubi [A] time = 0.185857, antiderivative size = 214, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 4, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.182, Rules used = {78, 50, 63, 208} \[ \frac{(d+e x)^{5/2} (-7 a B e+5 A b e+2 b B d)}{5 b^2 (b d-a e)}+\frac{(d+e x)^{3/2} (-7 a B e+5 A b e+2 b B d)}{3 b^3}+\frac{\sqrt{d+e x} (b d-a e) (-7 a B e+5 A b e+2 b B d)}{b^4}-\frac{(b d-a e)^{3/2} (-7 a B e+5 A b e+2 b B d) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{b^{9/2}}-\frac{(d+e x)^{7/2} (A b-a B)}{b (a+b x) (b d-a e)} \]
Antiderivative was successfully verified.
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Rule 78
Rule 50
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{(A+B x) (d+e x)^{5/2}}{(a+b x)^2} \, dx &=-\frac{(A b-a B) (d+e x)^{7/2}}{b (b d-a e) (a+b x)}+\frac{(2 b B d+5 A b e-7 a B e) \int \frac{(d+e x)^{5/2}}{a+b x} \, dx}{2 b (b d-a e)}\\ &=\frac{(2 b B d+5 A b e-7 a B e) (d+e x)^{5/2}}{5 b^2 (b d-a e)}-\frac{(A b-a B) (d+e x)^{7/2}}{b (b d-a e) (a+b x)}+\frac{(2 b B d+5 A b e-7 a B e) \int \frac{(d+e x)^{3/2}}{a+b x} \, dx}{2 b^2}\\ &=\frac{(2 b B d+5 A b e-7 a B e) (d+e x)^{3/2}}{3 b^3}+\frac{(2 b B d+5 A b e-7 a B e) (d+e x)^{5/2}}{5 b^2 (b d-a e)}-\frac{(A b-a B) (d+e x)^{7/2}}{b (b d-a e) (a+b x)}+\frac{((b d-a e) (2 b B d+5 A b e-7 a B e)) \int \frac{\sqrt{d+e x}}{a+b x} \, dx}{2 b^3}\\ &=\frac{(b d-a e) (2 b B d+5 A b e-7 a B e) \sqrt{d+e x}}{b^4}+\frac{(2 b B d+5 A b e-7 a B e) (d+e x)^{3/2}}{3 b^3}+\frac{(2 b B d+5 A b e-7 a B e) (d+e x)^{5/2}}{5 b^2 (b d-a e)}-\frac{(A b-a B) (d+e x)^{7/2}}{b (b d-a e) (a+b x)}+\frac{\left ((b d-a e)^2 (2 b B d+5 A b e-7 a B e)\right ) \int \frac{1}{(a+b x) \sqrt{d+e x}} \, dx}{2 b^4}\\ &=\frac{(b d-a e) (2 b B d+5 A b e-7 a B e) \sqrt{d+e x}}{b^4}+\frac{(2 b B d+5 A b e-7 a B e) (d+e x)^{3/2}}{3 b^3}+\frac{(2 b B d+5 A b e-7 a B e) (d+e x)^{5/2}}{5 b^2 (b d-a e)}-\frac{(A b-a B) (d+e x)^{7/2}}{b (b d-a e) (a+b x)}+\frac{\left ((b d-a e)^2 (2 b B d+5 A b e-7 a B e)\right ) \operatorname{Subst}\left (\int \frac{1}{a-\frac{b d}{e}+\frac{b x^2}{e}} \, dx,x,\sqrt{d+e x}\right )}{b^4 e}\\ &=\frac{(b d-a e) (2 b B d+5 A b e-7 a B e) \sqrt{d+e x}}{b^4}+\frac{(2 b B d+5 A b e-7 a B e) (d+e x)^{3/2}}{3 b^3}+\frac{(2 b B d+5 A b e-7 a B e) (d+e x)^{5/2}}{5 b^2 (b d-a e)}-\frac{(A b-a B) (d+e x)^{7/2}}{b (b d-a e) (a+b x)}-\frac{(b d-a e)^{3/2} (2 b B d+5 A b e-7 a B e) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{b^{9/2}}\\ \end{align*}
Mathematica [A] time = 0.424883, size = 166, normalized size = 0.78 \[ \frac{\frac{2 \left (-\frac{7 a B e}{2}+\frac{5 A b e}{2}+b B d\right ) \left (5 (b d-a e) \left (\sqrt{b} \sqrt{d+e x} (-3 a e+4 b d+b e x)-3 (b d-a e)^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )\right )+3 b^{5/2} (d+e x)^{5/2}\right )}{15 b^{7/2}}+\frac{(d+e x)^{7/2} (a B-A b)}{a+b x}}{b (b d-a e)} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.019, size = 626, normalized size = 2.9 \begin{align*}{\frac{2\,B}{5\,{b}^{2}} \left ( ex+d \right ) ^{{\frac{5}{2}}}}+{\frac{2\,Ae}{3\,{b}^{2}} \left ( ex+d \right ) ^{{\frac{3}{2}}}}-{\frac{4\,Bae}{3\,{b}^{3}} \left ( ex+d \right ) ^{{\frac{3}{2}}}}+{\frac{2\,Bd}{3\,{b}^{2}} \left ( ex+d \right ) ^{{\frac{3}{2}}}}-4\,{\frac{aA{e}^{2}\sqrt{ex+d}}{{b}^{3}}}+4\,{\frac{Ade\sqrt{ex+d}}{{b}^{2}}}+6\,{\frac{B{a}^{2}{e}^{2}\sqrt{ex+d}}{{b}^{4}}}-8\,{\frac{Bade\sqrt{ex+d}}{{b}^{3}}}+2\,{\frac{B{d}^{2}\sqrt{ex+d}}{{b}^{2}}}-{\frac{A{a}^{2}{e}^{3}}{{b}^{3} \left ( bxe+ae \right ) }\sqrt{ex+d}}+2\,{\frac{\sqrt{ex+d}Aad{e}^{2}}{{b}^{2} \left ( bxe+ae \right ) }}-{\frac{A{d}^{2}e}{b \left ( bxe+ae \right ) }\sqrt{ex+d}}+{\frac{B{a}^{3}{e}^{3}}{{b}^{4} \left ( bxe+ae \right ) }\sqrt{ex+d}}-2\,{\frac{\sqrt{ex+d}B{a}^{2}d{e}^{2}}{{b}^{3} \left ( bxe+ae \right ) }}+{\frac{Ba{d}^{2}e}{{b}^{2} \left ( bxe+ae \right ) }\sqrt{ex+d}}+5\,{\frac{A{a}^{2}{e}^{3}}{{b}^{3}\sqrt{ \left ( ae-bd \right ) b}}\arctan \left ({\frac{b\sqrt{ex+d}}{\sqrt{ \left ( ae-bd \right ) b}}} \right ) }-10\,{\frac{Aad{e}^{2}}{{b}^{2}\sqrt{ \left ( ae-bd \right ) b}}\arctan \left ({\frac{b\sqrt{ex+d}}{\sqrt{ \left ( ae-bd \right ) b}}} \right ) }+5\,{\frac{A{d}^{2}e}{b\sqrt{ \left ( ae-bd \right ) b}}\arctan \left ({\frac{b\sqrt{ex+d}}{\sqrt{ \left ( ae-bd \right ) b}}} \right ) }-7\,{\frac{B{a}^{3}{e}^{3}}{{b}^{4}\sqrt{ \left ( ae-bd \right ) b}}\arctan \left ({\frac{b\sqrt{ex+d}}{\sqrt{ \left ( ae-bd \right ) b}}} \right ) }+16\,{\frac{B{a}^{2}d{e}^{2}}{{b}^{3}\sqrt{ \left ( ae-bd \right ) b}}\arctan \left ({\frac{b\sqrt{ex+d}}{\sqrt{ \left ( ae-bd \right ) b}}} \right ) }-11\,{\frac{Ba{d}^{2}e}{{b}^{2}\sqrt{ \left ( ae-bd \right ) b}}\arctan \left ({\frac{b\sqrt{ex+d}}{\sqrt{ \left ( ae-bd \right ) b}}} \right ) }+2\,{\frac{B{d}^{3}}{b\sqrt{ \left ( ae-bd \right ) b}}\arctan \left ({\frac{b\sqrt{ex+d}}{\sqrt{ \left ( ae-bd \right ) b}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.5248, size = 1439, normalized size = 6.72 \begin{align*} \left [-\frac{15 \,{\left (2 \, B a b^{2} d^{2} -{\left (9 \, B a^{2} b - 5 \, A a b^{2}\right )} d e +{\left (7 \, B a^{3} - 5 \, A a^{2} b\right )} e^{2} +{\left (2 \, B b^{3} d^{2} -{\left (9 \, B a b^{2} - 5 \, A b^{3}\right )} d e +{\left (7 \, B a^{2} b - 5 \, A a b^{2}\right )} e^{2}\right )} x\right )} \sqrt{\frac{b d - a e}{b}} \log \left (\frac{b e x + 2 \, b d - a e + 2 \, \sqrt{e x + d} b \sqrt{\frac{b d - a e}{b}}}{b x + a}\right ) - 2 \,{\left (6 \, B b^{3} e^{2} x^{3} +{\left (61 \, B a b^{2} - 15 \, A b^{3}\right )} d^{2} - 10 \,{\left (17 \, B a^{2} b - 10 \, A a b^{2}\right )} d e + 15 \,{\left (7 \, B a^{3} - 5 \, A a^{2} b\right )} e^{2} + 2 \,{\left (11 \, B b^{3} d e -{\left (7 \, B a b^{2} - 5 \, A b^{3}\right )} e^{2}\right )} x^{2} + 2 \,{\left (23 \, B b^{3} d^{2} -{\left (59 \, B a b^{2} - 35 \, A b^{3}\right )} d e + 5 \,{\left (7 \, B a^{2} b - 5 \, A a b^{2}\right )} e^{2}\right )} x\right )} \sqrt{e x + d}}{30 \,{\left (b^{5} x + a b^{4}\right )}}, -\frac{15 \,{\left (2 \, B a b^{2} d^{2} -{\left (9 \, B a^{2} b - 5 \, A a b^{2}\right )} d e +{\left (7 \, B a^{3} - 5 \, A a^{2} b\right )} e^{2} +{\left (2 \, B b^{3} d^{2} -{\left (9 \, B a b^{2} - 5 \, A b^{3}\right )} d e +{\left (7 \, B a^{2} b - 5 \, A a b^{2}\right )} e^{2}\right )} x\right )} \sqrt{-\frac{b d - a e}{b}} \arctan \left (-\frac{\sqrt{e x + d} b \sqrt{-\frac{b d - a e}{b}}}{b d - a e}\right ) -{\left (6 \, B b^{3} e^{2} x^{3} +{\left (61 \, B a b^{2} - 15 \, A b^{3}\right )} d^{2} - 10 \,{\left (17 \, B a^{2} b - 10 \, A a b^{2}\right )} d e + 15 \,{\left (7 \, B a^{3} - 5 \, A a^{2} b\right )} e^{2} + 2 \,{\left (11 \, B b^{3} d e -{\left (7 \, B a b^{2} - 5 \, A b^{3}\right )} e^{2}\right )} x^{2} + 2 \,{\left (23 \, B b^{3} d^{2} -{\left (59 \, B a b^{2} - 35 \, A b^{3}\right )} d e + 5 \,{\left (7 \, B a^{2} b - 5 \, A a b^{2}\right )} e^{2}\right )} x\right )} \sqrt{e x + d}}{15 \,{\left (b^{5} x + a b^{4}\right )}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 2.31534, size = 540, normalized size = 2.52 \begin{align*} \frac{{\left (2 \, B b^{3} d^{3} - 11 \, B a b^{2} d^{2} e + 5 \, A b^{3} d^{2} e + 16 \, B a^{2} b d e^{2} - 10 \, A a b^{2} d e^{2} - 7 \, B a^{3} e^{3} + 5 \, A a^{2} b e^{3}\right )} \arctan \left (\frac{\sqrt{x e + d} b}{\sqrt{-b^{2} d + a b e}}\right )}{\sqrt{-b^{2} d + a b e} b^{4}} + \frac{\sqrt{x e + d} B a b^{2} d^{2} e - \sqrt{x e + d} A b^{3} d^{2} e - 2 \, \sqrt{x e + d} B a^{2} b d e^{2} + 2 \, \sqrt{x e + d} A a b^{2} d e^{2} + \sqrt{x e + d} B a^{3} e^{3} - \sqrt{x e + d} A a^{2} b e^{3}}{{\left ({\left (x e + d\right )} b - b d + a e\right )} b^{4}} + \frac{2 \,{\left (3 \,{\left (x e + d\right )}^{\frac{5}{2}} B b^{8} + 5 \,{\left (x e + d\right )}^{\frac{3}{2}} B b^{8} d + 15 \, \sqrt{x e + d} B b^{8} d^{2} - 10 \,{\left (x e + d\right )}^{\frac{3}{2}} B a b^{7} e + 5 \,{\left (x e + d\right )}^{\frac{3}{2}} A b^{8} e - 60 \, \sqrt{x e + d} B a b^{7} d e + 30 \, \sqrt{x e + d} A b^{8} d e + 45 \, \sqrt{x e + d} B a^{2} b^{6} e^{2} - 30 \, \sqrt{x e + d} A a b^{7} e^{2}\right )}}{15 \, b^{10}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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